Optimal. Leaf size=75 \[ \frac{(a+b) \sin (e+f x)}{a b f \sqrt{a+b \sin ^2(e+f x)}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^{3/2} f} \]
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Rubi [A] time = 0.10049, antiderivative size = 75, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.16, Rules used = {3190, 385, 217, 206} \[ \frac{(a+b) \sin (e+f x)}{a b f \sqrt{a+b \sin ^2(e+f x)}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^{3/2} f} \]
Antiderivative was successfully verified.
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Rule 3190
Rule 385
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{\cos ^3(e+f x)}{\left (a+b \sin ^2(e+f x)\right )^{3/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1-x^2}{\left (a+b x^2\right )^{3/2}} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{(a+b) \sin (e+f x)}{a b f \sqrt{a+b \sin ^2(e+f x)}}-\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{b f}\\ &=\frac{(a+b) \sin (e+f x)}{a b f \sqrt{a+b \sin ^2(e+f x)}}-\frac{\operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{\sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b f}\\ &=-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^{3/2} f}+\frac{(a+b) \sin (e+f x)}{a b f \sqrt{a+b \sin ^2(e+f x)}}\\ \end{align*}
Mathematica [A] time = 0.178865, size = 88, normalized size = 1.17 \[ \frac{\sqrt{b} (a+b) \sin (e+f x)-a^{3/2} \sqrt{\frac{b \sin ^2(e+f x)}{a}+1} \sinh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a}}\right )}{a b^{3/2} f \sqrt{a+b \sin ^2(e+f x)}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.946, size = 90, normalized size = 1.2 \begin{align*}{\frac{\sin \left ( fx+e \right ) }{bf}{\frac{1}{\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}}}-{\frac{1}{f}\ln \left ( \sin \left ( fx+e \right ) \sqrt{b}+\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}} \right ){b}^{-{\frac{3}{2}}}}+{\frac{\sin \left ( fx+e \right ) }{af}{\frac{1}{\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 4.04989, size = 1324, normalized size = 17.65 \begin{align*} \left [\frac{{\left (a b \cos \left (f x + e\right )^{2} - a^{2} - a b\right )} \sqrt{b} \log \left (128 \, b^{4} \cos \left (f x + e\right )^{8} - 256 \,{\left (a b^{3} + 2 \, b^{4}\right )} \cos \left (f x + e\right )^{6} + 32 \,{\left (5 \, a^{2} b^{2} + 24 \, a b^{3} + 24 \, b^{4}\right )} \cos \left (f x + e\right )^{4} + a^{4} + 32 \, a^{3} b + 160 \, a^{2} b^{2} + 256 \, a b^{3} + 128 \, b^{4} - 32 \,{\left (a^{3} b + 10 \, a^{2} b^{2} + 24 \, a b^{3} + 16 \, b^{4}\right )} \cos \left (f x + e\right )^{2} + 8 \,{\left (16 \, b^{3} \cos \left (f x + e\right )^{6} - 24 \,{\left (a b^{2} + 2 \, b^{3}\right )} \cos \left (f x + e\right )^{4} - a^{3} - 10 \, a^{2} b - 24 \, a b^{2} - 16 \, b^{3} + 2 \,{\left (5 \, a^{2} b + 24 \, a b^{2} + 24 \, b^{3}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sqrt{b} \sin \left (f x + e\right )\right ) - 8 \, \sqrt{-b \cos \left (f x + e\right )^{2} + a + b}{\left (a b + b^{2}\right )} \sin \left (f x + e\right )}{8 \,{\left (a b^{3} f \cos \left (f x + e\right )^{2} -{\left (a^{2} b^{2} + a b^{3}\right )} f\right )}}, \frac{{\left (a b \cos \left (f x + e\right )^{2} - a^{2} - a b\right )} \sqrt{-b} \arctan \left (\frac{{\left (8 \, b^{2} \cos \left (f x + e\right )^{4} - 8 \,{\left (a b + 2 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + a^{2} + 8 \, a b + 8 \, b^{2}\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sqrt{-b}}{4 \,{\left (2 \, b^{3} \cos \left (f x + e\right )^{4} + a^{2} b + 3 \, a b^{2} + 2 \, b^{3} -{\left (3 \, a b^{2} + 4 \, b^{3}\right )} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )}\right ) - 4 \, \sqrt{-b \cos \left (f x + e\right )^{2} + a + b}{\left (a b + b^{2}\right )} \sin \left (f x + e\right )}{4 \,{\left (a b^{3} f \cos \left (f x + e\right )^{2} -{\left (a^{2} b^{2} + a b^{3}\right )} f\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.37571, size = 96, normalized size = 1.28 \begin{align*} \frac{\frac{\log \left ({\left | -\sqrt{b} \sin \left (f x + e\right ) + \sqrt{b \sin \left (f x + e\right )^{2} + a} \right |}\right )}{b^{\frac{3}{2}}} + \frac{{\left (a + b\right )} \sin \left (f x + e\right )}{\sqrt{b \sin \left (f x + e\right )^{2} + a} a b}}{f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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